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ios string分割字符串

可以用NSString类的 - (NSArray *)componentsSeparatedByString:(NSString *)separator函数实现。 例子: 假如有一个字符串 NSString *list = @"Karin, Carrie, David"; 可以用上面的函数得到一个字符串数组: NSArray *listItems = [list compo...

NSString * str = @"a b csdf swe";NSArray * arr = [str componentsSeparatedByString:@" "];结果: 不需要间隔字符的方法: NSString * str = @"hello"NSMutableArray * arr = [NSMutableArray arrayWithCapacity:0]; // 遍历字符串,按字符来...

IOS字符串按特定字符拆分成数组 NSString * fruits = @"apple,pair,banana,orange";NSArray * array= [fruits componentsSeparatedByString:@","];

[原字符串 stringByReplacingOccurrencesOfString:@"目标字符串" withString:@"要替换的字符串"]

分类: iOS(34) 1.定义一个字符串a, 截取a 的某一个项目组,复制给b, b必须是int型 NSString *a = @"1.2.30"; int b= [[a substringWithRange:NSMakeRange(4,2)] intValue]; NSLog(@"a:%@ \n",a ); NSLog(@"b:%d",b ); Outpu...

NSString *string = [array componentsJoinedByString:@","];--分隔符

NSRange range = [str rangeOfString:@"aaa"]; //现获取要截取的字符串位置 NSString * result = [str substringFromIndex:range.location]; //截取字符串 希望可以帮到你!

/*! * @brief 把格式化的JSON格式的字符串转换成字典 * @param jsonString JSON格式的字符串 * @return 返回字典 */+ (NSDictionary *)dictionaryWithJsonString:(NSString *)jsonString { if (jsonString == nil) { return nil; } NSData *json...

//有两种方法 NSString *originalString = @"I wanna go to the Rio Olympics"; //1.substringFromIndex: 从第18位字符开始到最后的字符的字符串截取 NSString *subfixString = [originalString substringFromIndex:18]; //2.substringWithRange...

NSString *string = @"qwer"; NSMutableString *newString = [[NSMutableString alloc] initWithCapacity:string.length]; for (int i = string.length - 1; i >=0 ; i --) { unichar ch = [string characterAtIndex:i]; [newString appendForma...

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